('+OK 729 octets', ['Received: from xxx.xxx (cmung805.xxx.xxxx.hr
[255.255.255.43])', '\tby xxx.xxx.hr (8.12.9/8.12.5) with ESMTP id
h5GJxhh8004116', '\tfor <[email protected]>; Mon, 16 Jun 2003
21:59:43 +0200 (MEST)', 'Date: Mon, 16 Jun 2003 21:59:43 +0200 (MEST)',
'Message-Id: <[email protected]>', 'From:
[email protected]', 'To: [email protected]', 'Subject:
GPG public key', 'X-Virus-Scanned: by amavisd-milter at xxx.xxx.hr', 'Content-Length:
237', 'Status: O', '', '', -----BEGIN PGP PUBLIC KEY BLOCK-----
Version: GnuPG v1.0.6 (GNU/Linux)
Comment: For info see http://www.gnupg.org
mQGiBD7adigRBACicZVTbq0WNn95UBnPFIEQWFrZCt6d8AIhXRG1VVJlHkjD9zxO
-----END PGP PUBLIC KEY BLOCK-----)
mene zanima kako da napravim da skripta ekstrakta ono sto je unutar -----BEGIN PGP PUBLIC KEY BLOCK----- i -----END PGP PUBLIC KEY BLOCK-----? Dakle kako da izvadim sami public key? Pokusavam s regexima vec dva dana kao sto rekoh, ali nikako ne uspjevam.
Stvarno vam hvala na bilo kakvoj pomoci, ni ne znate koje ste mi muke skratili;)